From 1a6f5e061bf86d692e1a0fba50369014a79e5533 Mon Sep 17 00:00:00 2001 From: Danila Fedorin Date: Sun, 29 Jan 2023 21:00:22 -0800 Subject: [PATCH] Add a very rough draft of the idris catemorphisms article I found lying around --- content/blog/idris_catamorphisms.md | 47 +++++++++++++++++++++++++++++ 1 file changed, 47 insertions(+) create mode 100644 content/blog/idris_catamorphisms.md diff --git a/content/blog/idris_catamorphisms.md b/content/blog/idris_catamorphisms.md new file mode 100644 index 0000000..6298228 --- /dev/null +++ b/content/blog/idris_catamorphisms.md @@ -0,0 +1,47 @@ +--- +title: "Induction Principles from Base Functors" +date: 2022-04-22T12:19:22-07:00 +tags: ["Idris"] +draft: true +--- +In the [Haskell catamorphisms article]({{< relref "haskell_catamorphisms" >}}), we looked +at how base functors and functions of the type `F a -> a` can be used to +derive "fold" functions on inductive data types. This formulation allows for +one more interesting trick, one that I found to be extremely interesting and +worth covering. However, this trick requires a more powerful type system +than Haskell provides us; it requires depdendent types. + +This article assumes a working knowledge of dependent types. I will not +spend time explaining dependent types, nor the syntax for them in Idris, +which is the language I'll use in this article. Below are a few resources +that should help you get up to speed. + +{{< todo >}}List resources{{< /todo >}} + +We've seen that, given a function `F a -> a`, we can define a function +`B -> a`, if `F` is a base functor of the type `B`. However, what if +the goal is to define a function in which the return type `a` depends +on the value of `B`? In other words, what if we want to define a function +with type: +```Idris +someFunction : (b : B) -> P b +``` +How might we achieve such a thing? Unlike the generic type `a`, we can't +simply place `P` into the base functor `F`; the following is completely +invalid. +```Idris +-- Completely bogus +argType : Type +argType = F P -> P +``` +In our case, `P` is a type family, rather than a type; in order to use it as +a parameter to the base functor, we need to feed it an argument (of type `B`). +Well, we've already seen one way to get a value `b` of type `B` at the type +level: we can use a dependent function. This too is not correct, but it does get us a little bit closer to the goal. +```Idris +-- Still bogus +argType : Type +argType = (b : B) -> F (P b) -> P b +``` +Recall that the base functor `F` effectively denotes a single layer of a data +structure, with recursive