Add a generic Map module and prove its induced equivalence relation
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51
Lattice.agda
51
Lattice.agda
@@ -1,7 +1,7 @@
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module Lattice where
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import Data.Nat.Properties as NatProps
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open import Relation.Binary.PropositionalEquality as Eq using (_≡_; sym; isEquivalence)
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open import Relation.Binary.PropositionalEquality as Eq using (_≡_; sym)
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open import Relation.Binary.Definitions
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open import Data.Nat as Nat using (ℕ; _≤_)
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open import Data.Product using (_×_; _,_)
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@@ -68,6 +68,55 @@ record Lattice {a} (A : Set a) : Set (lsuc a) where
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open IsLattice isLattice public
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module IsEquivalenceInstances where
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module ForMap {a b} (A : Set a) (B : Set b)
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(≡-dec-A : Decidable (_≡_ {a} {A}))
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(_≈₂_ : B → B → Set b)
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(eB : IsEquivalence B _≈₂_) where
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open import Map A B ≡-dec-A using (Map; lift; subset; insert)
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open import Data.List using (_∷_; []) -- TODO: re-export these with nicer names from map
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open import Data.List.Relation.Unary.Any using (Any; here; there) -- TODO: re-export these with nicer names from map
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open IsEquivalence eB renaming
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( ≈-refl to ≈₂-refl
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; ≈-sym to ≈₂-sym
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; ≈-trans to ≈₂-trans
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)
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private
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_≈_ : Map → Map → Set (Agda.Primitive._⊔_ a b)
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_≈_ = lift _≈₂_
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_⊆_ : Map → Map → Set (Agda.Primitive._⊔_ a b)
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_⊆_ = subset _≈₂_
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⊆-refl : {m : Map} → m ⊆ m
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⊆-refl k v k,v∈m = (v , (≈₂-refl , k,v∈m))
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⊆-trans : {m₁ m₂ m₃ : Map} → m₁ ⊆ m₂ → m₂ ⊆ m₃ → m₁ ⊆ m₃
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⊆-trans m₁⊆m₂ m₂⊆m₃ k v k,v∈m₁ =
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let
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(v' , (v≈v' , k,v'∈m₂)) = m₁⊆m₂ k v k,v∈m₁
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(v'' , (v'≈v'' , k,v''∈m₃)) = m₂⊆m₃ k v' k,v'∈m₂
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in (v'' , (≈₂-trans v≈v' v'≈v'' , k,v''∈m₃))
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≈-refl : {m : Map} → m ≈ m
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≈-refl {m} = (⊆-refl , ⊆-refl)
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≈-sym : {m₁ m₂ : Map} → m₁ ≈ m₂ → m₂ ≈ m₁
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≈-sym (m₁⊆m₂ , m₂⊆m₁) = (m₂⊆m₁ , m₁⊆m₂)
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≈-trans : {m₁ m₂ m₃ : Map} → m₁ ≈ m₂ → m₂ ≈ m₃ → m₁ ≈ m₃
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≈-trans (m₁⊆m₂ , m₂⊆m₁) (m₂⊆m₃ , m₃⊆m₂) = (⊆-trans m₁⊆m₂ m₂⊆m₃ , ⊆-trans m₃⊆m₂ m₂⊆m₁)
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LiftEquivalence : IsEquivalence Map _≈_
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LiftEquivalence = record
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{ ≈-refl = ≈-refl
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; ≈-sym = ≈-sym
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; ≈-trans = ≈-trans
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}
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module IsSemilatticeInstances where
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module ForNat where
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open Nat
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