Remove sketch if proof since the proof is done
Signed-off-by: Danila Fedorin <danila.fedorin@gmail.com>
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@ -484,44 +484,6 @@ private
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indices-complete (suc n') zero = RelAny.here refl
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indices-complete (suc n') zero = RelAny.here refl
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indices-complete (suc n') (suc f') = RelAny.there (x∈xs⇒fx∈fxs suc (indices-complete n' f'))
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indices-complete (suc n') (suc f') = RelAny.there (x∈xs⇒fx∈fxs suc (indices-complete n' f'))
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-- Sketch, 'build control flow graph'
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-- -- Create new block, mark it as the current insertion point.
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-- emptyBlock : m Id
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-- currentBlock : m Id
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-- -- Create a new block, and insert the statement into it. Shold restore insertion pont.
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-- createBlock : Stmt → m (Id × Id)
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-- -- Note that the given ID is a successor / predecessor of the given
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-- -- insertion point.
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-- noteSuccessor : Id → m ()
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-- notePredecessor : Id → m ()
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-- noteEdge : Id → Id → m ()
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-- -- Insert the given statment into the current insertion point.
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-- buildCfg : Stmt → m Cfg
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-- buildCfg { bs₁ } = push bs₁
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-- buildCfg (s₁ ; s₂ ) = buildCfg s₁ >> buildCfg s₂
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-- buildCfg (if _ then s₁ else s₂) = do
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-- (b₁ , b₁') ← createBlock s₁
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-- noteSuccessor b₁
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-- (b₂ , b₂') ← createBlock s₂
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-- noteSuccessor b₂
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-- b ← emptyBlock
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-- notePredecessor b₁'
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-- notePredecessor b₂'
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-- buildCfg (while e repeat s) = do
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-- (b₁, b₁') ← createBlock s
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-- noteSuccessor b₁
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-- noteEdge b₁' b₁
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-- b ← emptyBlock
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-- notePredecessor b₁'
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-- For now, just represent the program and CFG as one type, without branching.
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-- For now, just represent the program and CFG as one type, without branching.
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record Program : Set where
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record Program : Set where
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