Move proof of least element into FiniteHeightLattice

Signed-off-by: Danila Fedorin <danila.fedorin@gmail.com>
This commit is contained in:
2025-07-26 13:16:22 +02:00
parent d99d4a2893
commit f5457d8841
4 changed files with 31 additions and 22 deletions

View File

@@ -5,8 +5,8 @@ module Fixedpoint {a} {A : Set a}
{h : }
{_≈_ : A A Set a}
{_⊔_ : A A A} {_⊓_ : A A A}
(≈-Decidable : IsDecidable _≈_)
(flA : IsFiniteHeightLattice A h _≈_ _⊔_ _⊓_)
{{ ≈-Decidable : IsDecidable _≈_ }}
{{flA : IsFiniteHeightLattice A h _≈_ _⊔_ _⊓_}}
(f : A A)
(Monotonicᶠ : Monotonic (IsFiniteHeightLattice._≼_ flA)
(IsFiniteHeightLattice._≼_ flA) f) where
@@ -28,24 +28,9 @@ private
using ()
renaming
( to ⊥ᴬ
; longestChain to longestChainᴬ
; bounded to boundedᴬ
)
⊥ᴬ≼ : (a : A) ⊥ᴬ a
⊥ᴬ≼ a with ≈-dec a ⊥ᴬ
... | yes a≈⊥ᴬ = ≼-cong a≈⊥ᴬ ≈-refl (≼-refl a)
... | no a̷≈⊥ᴬ with ≈-dec ⊥ᴬ (a ⊥ᴬ)
... | yes ⊥ᴬ≈a⊓⊥ᴬ = ≈-trans (⊔-comm ⊥ᴬ a) (≈-trans (≈-⊔-cong (≈-refl {a}) ⊥ᴬ≈a⊓⊥ᴬ) (absorb-⊔-⊓ a ⊥ᴬ))
... | no ⊥ᴬ̷≈a⊓⊥ᴬ = ⊥-elim (ChainA.Bounded-suc-n boundedᴬ (ChainA.step x≺⊥ᴬ ≈-refl longestChainᴬ))
where
⊥ᴬ⊓a̷≈⊥ᴬ : ¬ (⊥ᴬ a) ⊥ᴬ
⊥ᴬ⊓a̷≈⊥ᴬ = λ ⊥ᴬ⊓a≈⊥ᴬ ⊥ᴬ̷≈a⊓⊥ᴬ (≈-trans (≈-sym ⊥ᴬ⊓a≈⊥ᴬ) (⊓-comm _ _))
x≺⊥ᴬ : (⊥ᴬ a) ⊥ᴬ
x≺⊥ᴬ = (≈-trans (⊔-comm _ _) (≈-trans (≈-refl {⊥ᴬ (⊥ᴬ a)}) (absorb-⊔-⊓ ⊥ᴬ a)) , ⊥ᴬ⊓a̷≈⊥ᴬ)
-- using 'g', for gas, here helps make sure the function terminates.
-- since A forms a fixed-height lattice, we must find a solution after
-- 'h' steps at most. Gas is set up such that as soon as it runs
@@ -65,7 +50,7 @@ private
c' rewrite +-comm 1 hᶜ = ChainA.concat c (ChainA.step a₂≺fa₂ ≈-refl (ChainA.done (≈-refl {f a₂})))
fix : Σ A (λ a a f a)
fix = doStep (suc h) 0 ⊥ᴬ ⊥ᴬ (ChainA.done ≈-refl) (+-comm (suc h) 0) ( (f ⊥ᴬ))
fix = doStep (suc h) 0 ⊥ᴬ ⊥ᴬ (ChainA.done ≈-refl) (+-comm (suc h) 0) (⊥≼ (f ⊥ᴬ))
aᶠ : A
aᶠ = proj₁ fix
@@ -85,4 +70,4 @@ private
... | no _ = stepPreservesLess g' _ _ _ b b≈fb (≼-cong ≈-refl (≈-sym b≈fb) (Monotonicᶠ a₂≼b)) _ _ _
aᶠ≼ : (a : A) a f a aᶠ a
aᶠ≼ a a≈fa = stepPreservesLess (suc h) 0 ⊥ᴬ ⊥ᴬ a a≈fa ( a) (ChainA.done ≈-refl) (+-comm (suc h) 0) ( (f ⊥ᴬ))
aᶠ≼ a a≈fa = stepPreservesLess (suc h) 0 ⊥ᴬ ⊥ᴬ a a≈fa (⊥≼ a) (ChainA.done ≈-refl) (+-comm (suc h) 0) (⊥≼ (f ⊥ᴬ))