Don't encode '\n' for now
Signed-off-by: Danila Fedorin <danila.fedorin@gmail.com>
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@ -14,8 +14,6 @@ decodeStr str =
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let
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go l =
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case l of
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'\\' :: 'n' :: rest -> '\n' :: go rest
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'\\' :: '\\' :: rest -> '\\' :: go rest
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'\\' :: '"' :: rest -> '"' :: go rest
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'\\' :: c :: rest -> c :: go rest
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c :: rest -> c :: go rest
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