Fix typos
Signed-off-by: Danila Fedorin <danila.fedorin@gmail.com>
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@ -207,7 +207,7 @@ At first, the exercise may not obviously correspond to the bulk operation
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I've described. Particularly confusing is the fact that it has two lattices,
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\(L_1\) and \(L_2\). In fact, the exercise results in a very general theorem;
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we can exploit a more concrete version of the theorem by setting
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\(L_1 \triangleq A \to L_2\), resulting in an overal signature for \(f\) and \(h\):
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\(L_1 \triangleq A \to L_2\), resulting in an overall signature for \(f\) and \(h\):
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{{< latex >}}
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f : (A \to L_2) \to (A \to L_2)
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