Add draft of boolean values post.
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---
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title: "How Many Values Does a Boolean Have?"
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date: 2020-08-20T18:37:50-07:00
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draft: ["Java", "Haskell"]
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---
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A friend of mine recently had an interview for a software
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engineering position. They later recounted to me the content
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of the techical questions that they had been asked. Some had
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been pretty standard:
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* __"What's the difference between concurrency
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and parallelism?"__ -- a reasonable question given that Go was
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the company's language of choice.
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* __"What's the difference between a method and a function?"__ --
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a little more strange, in my opinion, since the difference
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is of little _practical_ use.
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But then, they recounted a rather interesting question:
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> How many values does a bool have?
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Innocous at first, isn't it? Probably a bit simpler, in fact,
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than the questions about methods and functions, concurrency
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and parallelism. It's plausible that a programmer
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has not done much concurrent or parallel programming in their
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life, or that they came from a language in which functions
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were rare and methods were ubiquitous. It's not plausible,
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on the other hand, that a candidate applying to a software
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engineering position has not encountered booleans.
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If you're genuinely unsure about the answer to the question,
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I think there's no reason for me to mess with you. The
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simple answer to the question -- as far as I know -- is that a boolean
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has two values. They are `true` and `false` in Java, or `True` and `False`
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in Haskell, and `1` and `0` in C. A boolean value is either true or false.
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So, what's there to think about? There are a few things, _ackshually_.
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Let's explore them, starting from the theoretical perspective.
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### What's a Type, Anyway?
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Boolean, or `bool`, is a type. Broadly speaking, a type
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is a property of _something_ that defines what the _something_
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means and what you can do with it. That _something_ can be
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several things; for our purposes, it can either be an
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_expression_ in a programming language (in the form of `fact(n)`)
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or a value in that same programming langauge (like `5`).
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Dealing with values is rather simple. Most languages have finite numbers,
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usually with \\(2^{32}\\) values, which have type `int`,
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`i32`, or something in a similar vein. Most languages also have
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strings, of which there are as many as you have memory to contain,
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and which have the type `string`, `String`, or occasianlly
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the more confusing `char*`. Most languages also have booleans,
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as we discussed above.
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The deal with expressions is a more interesting. Presumably
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expressions evaluate to values, and the type of an expression
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is then the type of values it can yield. Consider the following
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snippet in C++:
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```C
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int square(int x) {
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return x * x;
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}
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```
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Here, the expression `x` is known to have type `int` from
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the type signature provided by the user. Multiplication
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of integers yields an integer, and so the type of `x*x` is also
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of type `int`. Since `square(x)` returns `x*x`, it is also
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of type `int`. So far, so good.
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Okay, how about this:
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```C++
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int meaningOfLife() {
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return meaningOfLife();
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}
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```
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No, wait, doesn't say "stack overflow" just yet. That's no fun.
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And anyway, this is technically a tail call, so maybe our
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C++ compiler can avoid growing the stack And indeed,
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flicking on the `-O2` flag in this [compiler explorer example](https://godbolt.org/z/9cv4nY),
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we can see that no stack growth is necessary: it's just
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an infinite loop. But `meaningOfLife` will never return a value. One could say
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this computation _diverges_.
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Well, if it diverges, just throw the expression out of the window! That's
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no `int`! We only want _real_ `int`s!
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And here, we can do that. But what about the following:
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```C++
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inf_int collatz(inf_int x) {
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if(x == 1) return 1;
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if(x % 2 == 0) return collatz(x/2);
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return collatz(x * 3 + 1);
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}
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```
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Notice that I've used the fictitious type
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`inf_int` to represent integers that can hold
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arbitrarily large integer values, not just the 32-bit ones.
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That is important for this example, and I'll explain why shortly.
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The code in the example is a simulation of the process described
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in the [Collatz conjecture](https://en.wikipedia.org/wiki/Collatz_conjecture).
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Given an input number `x`, if the number is even, it's divided in half,
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and the process continues with the halved number. If, on the other
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hand, the number is odd, it's multiplied by 3, 1 is added to it,
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and the process continues with _that_ number. The only way for the
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process to terminate is for the computation to reach the value 1.
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Why does this matter? Because as of right now, __nobody knows__
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whether or not the process terminates for all possible input numbers.
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We have a strong hunch that it does; we've checked a __lot__
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of numbers and found that the process terminates for them.
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This is why 32-bit integers are not truly sufficient for this example;
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we know empirically that the function will terminate for them.
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But why does _this_ matter? Well, it matters because we don't know
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whether or not this function will diverge, and thus, we can't
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'throw it out of the window' like we wanted to with `meaningOfLife`!
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In general, it's _impossible to tell_ whether or not a program will
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terminate; that is the [halting prorblem](https://en.wikipedia.org/wiki/Halting_problem).
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So, what do we do?
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It turns out to be convenient -- formally -- to treat the result of a diverging computation
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as its own value. This value is usually called 'bottom', and written as \\(\\bot\\).
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Since in most programming languages, you can write a nonterminating expression or
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function of any type, this 'bottom' is included in _all_ types. So in fact, the
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set of possible values for `unsigned int`: \\(\\bot, 0, 1, 2, ...\\) and so on.
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As you may have by now guessed, the same is true for a boolean: we have \\(\\bot\\), `true`, and `false`.
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### Haskell and Bottom
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You may be thinking:
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> Now he's done it; he's gone off the deep end with all that programming language
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theory. Tell me, Daniel, where the heck have you ever encountered \\(\\bot\\) in
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code? This question was for a software engineering interview, after all!
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You're right; I haven't _specifically_ seen the symbol \\(\\bot\\) in my time
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programming. But I have frequently used an equivalent notation for the same idea:
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`undefined`. In fact, here's a possible definition of `undefined` in Haskell:
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```
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undefined = undefined
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```
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Just like `meaningOfLife`, this is a divergent computation! What's more is that
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the type of this computation is, in Haskell, `a`. More explicitly -- and retreating
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to more mathematical notation -- we can write this type as: \\(\\forall \\alpha . \\alpha\\).
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That is, for any type \\(\\alpha\\), `undefined` has that type! This means
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`undefined` can take on _any_ type, and so, we can write:
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```Haskell
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myTrue :: Bool
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myTrue = True
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myFalse :: Bool
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myFalse = False
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myBool :: Bool
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myBool = undefined
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```
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In Haskell, this is quite useful. For instance, if one's in the middle
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of writing a complicated function, and wants to check their work so far,
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they can put 'undefined' for the part of the function they haven't written.
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They can then compile their program; the typechecker will find any mistakes
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they've made so far, but, since the type of `undefined` can be _anything_,
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that part of the program will be accepted without second thought.
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The language `Idris` extends this practice with the idea of typed holes,
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where you can leave fragments of your program unwritten, and ask the
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compiler what kind of _thing_ you need to write to fill that hole.
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### Java and `null`
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Now you may be thinking:
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> This whole deal with Haskell's `undefined` is beside the point; it doesn't
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really count as a value, since it's just a nonterminating
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expression. What you're doing is a kind of academic autofellatio.
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Alright, I can accept this criticism. Perhaps just calling a nonterminating
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function a value _is_ far-fetched (even though denotational semantics
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_do_ extend types with \\(\\bot\\)). But denotational semantics is not
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the only place where types are implcitily extend with an extra value;
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let's look at Java.
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In Java, we have `null`. At the
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core language level, any function or method that accepts a class can also take `null`;
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if `null` is not to that function or method's liking, it has to
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explicitly check for it using `if(x == null)`.
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Java's booleans are not, at first glance, classes. Unlike classes, which you have
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to allocate using `new`, you can just throw around `true` and `false` as you see
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fit. Also unlike classes, you can't assign `null` to a boolean value.
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The trouble is, the _generics_ part of Java, which allows you to write
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polymorphic functions, can't handle 'primitives' like `bool`. If you want to have an `ArrayList`
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of something, that something _must_ be a class.
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But what if you really _do_ want an `ArrayList` of booleans? Java solves this problem by introducing
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'boxed' booleans: they're primitives wrapped in a class, called `Boolean`. This class
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can then be used for generics.
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But see, this is where `null` has snuck in again. By allowing `Boolean` to be a class
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(thereby granting it access to generics), we've also given it the ability to be null.
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This example is made especially compelling because Java supports something
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they call [autoboxing](https://docs.oracle.com/javase/tutorial/java/data/autoboxing.html):
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you can directly assign a primitive to a variable of the corresponding boxed type.
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Consider the example:
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```Java
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Boolean myTrue = true;
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Boolean myFalse = false;
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Boolean myBool = null;
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```
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